MayaK. asked • 05/02/20 If tan x° = 6 divided by g and sin x° = 6 divided by h, what is the value of cos x°? cos x° = h divided by g cos x° = g divided by h cos x° = gh cos x° = 6g
Thesolutions are S={1/2pi, 3/2pi, 1/6pi, 5/6pi} We need sin2x=2sinxcosx Therefore, sin2x=cosx sin2x-cosx=0 2sinxcosx-cosx=0 cosx(2sinx-1)=0 So, {(cosx=0),(2sinx-1=0
TheLaw of Sines. The Law of Sines (or Sine Rule) is very useful for solving triangles: a sin A = b sin B = c sin C. It works for any triangle: a, b and c are sides. A, B and C are angles. (Side a faces angle A, side b faces angle B and. side c faces angle C).
Integralof cos2x/ (cosx+sinx)^2. We integrate the function, which is cos2x divided by cos x plus sine x, to the power two dx. Now we are breaking the numeral using cos2x. However, we know that cos2x equals cos square x minus sine square x.
. sinθ 1 + cosθ = 2sin(θ 2)cos(θ 2) 2cos2(θ 2) = sin(θ 2) cos(θ 2) = tan( θ 2). Answer link. sin theta/ (1+cos theta) = csc theta-cot theta I'm not sure what you are wanting, but here's one way to simplify the expression: sin theta/ (1+cos theta) = (sin theta (1-cos theta))/ ( (1+cos theta) (1-cos theta)) color (white) (sin
2 these series include the approximation for cos(x) and sin(x). I'm doing a class on Complex Calculus and series are a part of the program. Comment Button Cosine of x is all of the even powers of x divided by that power's factorial. Sine of x, when you take its polynomial representation, is all of the odd powers of x divided by its
CofunctionIdentities (in Degrees) The co-function or periodic identities can also be represented in degrees as: sin (90°−x) = cos x. cos (90°−x) = sin x. tan (90°−x) = cot x. cot (90°−x) = tan x. sec (90°−x) = cosec x. cosec (90°−x) = sec x.
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what is cos x divided by sin x
